select case when a.cnt = b.cnt then '两个库结构一致'when a.cnt <> b.cnt then '两个库结构不一致' endfrom (select count(*) as cntfrom dba_tab_columns t1, dba_tab_columns@lnk_db2 t2where t1.owner = 'TAOBAO'and t1.owner = t2.ownerand t1.table_name = t2.table_nameand t1.column_name = t2.column_nameand t1.data_type = t2.data_typeand t1.data_length = t2.data_lengthand t1.nullable = t2.nullableand nvl(t1.data_PRecision, 0) = nvl(t2.data_precision, 0)and nvl(t1.data_scale, 0) = nvl(t2.data_scale, 0)) a,(select count(*) as cntfrom dba_tab_columnswhere owner = 'TAOBAO') b 新闻热点
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