在网上见到一个oracle的版本的小写转大写金额的函数，感觉还不错现在把它转成sql server版本。
/********************************************************
作者：([email protected])
版本：1.0
创建时间：20020227
修改时间：
功能：小写金额转换成大写
参数：n_lowermoney 小写金额
v_transtype 种类 -- 1: directly translate, 0: read it in words
输出：大写金额
********************************************************/
create function dbo.l2u (@n_lowermoney numeric(15,2),@v_transtype int)
returns varchar(200) as
begin
declare @v_lowerstr varchar(200) -- 小写金额
declare @v_upperpart varchar(200)
declare @v_upperstr varchar(200) -- 大写金额
declare @i_i int
set @v_lowerstr = ltrim(rtrim(round(@n_lowermoney,2))) --四舍五入为指定的精度并删除数据左右空格
set @i_i = 1
set @v_upperstr = ''
while ( @i_i <= len(@v_lowerstr))
begin
select @v_upperpart = case substring(@v_lowerstr,len(@v_lowerstr) - @i_i + 1,1)
when '.' then '元'
when '0' then '零'
when '1' then '壹'
when '2' then '贰'
when '3' then '叁'
when '4' then '肆'
when '5' then '伍'
when '6' then '陆'
when '7' then '柒'
when '8' then '捌'
when '9' then '玖'
end
+
case @i_i
when 1 then '分'
when 2 then '角'
when 3 then ''
when 4 then ''
when 5 then '拾'
when 6 then '佰'
when 7 then '仟'
when 8 then '万'
when 9 then '拾'
when 10 then '佰'
when 11 then '仟'
when 12 then '亿'
when 13 then '拾'
when 14 then '佰'
when 15 then '仟'
when 16 then '万'
else ''
end
set @v_upperstr = @v_upperpart + @v_upperstr
set @i_i = @i_i + 1
end
if ( 0 = @v_transtype)
begin
set @v_upperstr = replace(@v_upperstr,'零拾','零')
set @v_upperstr = replace(@v_upperstr,'零佰','零')
set @v_upperstr = replace(@v_upperstr,'零仟','零')
set @v_upperstr = replace(@v_upperstr,'零零零','零')
set @v_upperstr = replace(@v_upperstr,'零零','零')
set @v_upperstr = replace(@v_upperstr,'零角零分','整')
set @v_upperstr = replace(@v_upperstr,'零分','整')
set @v_upperstr = replace(@v_upperstr,'零角','零')
set @v_upperstr = replace(@v_upperstr,'零亿零万零元','亿元')
set @v_upperstr = replace(@v_upperstr,'亿零万零元','亿元')
set @v_upperstr = replace(@v_upperstr,'零亿零万','亿')
set @v_upperstr = replace(@v_upperstr,'零万零元','万元')
set @v_upperstr = replace(@v_upperstr,'万零元','万元')
set @v_upperstr = replace(@v_upperstr,'零亿','亿')
set @v_upperstr = replace(@v_upperstr,'零万','万')
set @v_upperstr = replace(@v_upperstr,'零元','元')
set @v_upperstr = replace(@v_upperstr,'零零','零')
end
-- 对壹元以下的金额的处理
if ( '元' = substring(@v_upperstr,1,1))
begin
set @v_upperstr = substring(@v_upperstr,2,(len(@v_upperstr) - 1))
end
if ( '零' = substring(@v_upperstr,1,1))
begin
set @v_upperstr = substring(@v_upperstr,2,(len(@v_upperstr) - 1))
end
if ( '角' = substring(@v_upperstr,1,1))
begin
set @v_upperstr = substring(@v_upperstr,2,(len(@v_upperstr) - 1))
end
if ( '分' = substring(@v_upperstr,1,1))
begin
set @v_upperstr = substring(@v_upperstr,2,(len(@v_upperstr) - 1))
end
if ('整' = substring(@v_upperstr,1,1))
begin
set @v_upperstr = '零元整'
end
return @v_upperstr
end
例子：
select dbo.l2u(56588441.111,0)
select dbo.l2u(00.00,0)
