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Kotlin 基础教程之数组容器

2024-07-13 10:09:27
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Kotlin 基础教程之数组容器

Arrays

Kotlin 标准库提供了arrayOf()创建数组, **ArrayOf创建特定类型数组

val array = arrayOf(1, 2, 3)val countries = arrayOf("UK", "Germany", "Italy")val numbers = intArrayOf(10, 20, 30)val array1 = Array(10, { k -> k * k })val longArray = emptyArray<Long>()val studentArray = Array<Student>(2)studentArray[0] = Student("james")

和Java不一样,Kotlin 的数组是容器类, 提供了 ByteArray, CharArray, ShortArray, IntArray, LongArray, BooleanArray, FloatArray, and DoubleArray。

Lists

List是有序容器,Kotlin 标准库通过listOf()创建list

val intList: List<Int> = listOf(20, 5, 10)val emptyList: List<String> = emptyList<String>()val nonNulls: List<String> = listOfNotNull<String>(null, "a", "b", "c")val doubleList: ArrayList<Double> = arrayListOf(84.88, 100.25, 999.99)

其中,intList, emptyList, nonNulls是只读的实例,要修改这些list,需要进行类型转换

(intList as AbstractList<Int>).set(0, 30)(nonNulls as java.util.ArrayList).addAll(arrayOf("x", "y"))

Maps

Map是<key, value>容器, Kotlin提供mapOf创建map

val map = mapOf("a" to 1, "b" to 2, "c" to 3)val value = map.get(b)val states: MutableMap<String, String>= mutableMapOf("AL" to "Alabama",     "AK" to "Alaska", "AZ" to "Arizona")val customers: java.util.HashMap<Int, Customer> = hashMapOf(1 to    Customer("Dina", "Kreps", 1), 2 to Customer("Andy", "Smith", 2))val linkedHashMap: java.util.LinkedHashMap<String, String> =    linkedMapOf("red" to "#FF0000","azure" to "#F0FFFF","white" to "#FFFFFF")val sortedMap: java.util.SortedMap<Int, String> = sortedMapOf(4 to "d",    1 to "a", 3 to "c", 2 to "b")

Sets

Set是没有重复项的容器, Kotlin提供setOf创建Set

val intSet: Set<Int> = setOf(1, 21, 21, 2, 6, 3, 2) //1,21,2,6,3val hashSet: java.util.HashSet<Book> = hashSetOf(    Book("Jules Verne", "Around the World in 80 Days Paperback", 2014, "978-1503215153"),    Book("Jules Verne", "Around the World in 80 Days Paperback", 2014, "978-1503215153"))val sortedIntegers: java.util.TreeSet<Int> = sortedSetOf(11, 0, 9, 11, 9, 8)

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