Java中Json解析的方法分析

* String JsonStr = "{object:{persons:" +"[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," +"{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," +"{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}";* 然后定义一个Person类**class Person{  private String name,image;  public String getName() {    return name;  }  public void setName(String name) {    this.name = name;  }  public String getImage() {    return image;  }  public void setImage(String image) {    this.image = image;  }}

class MyDay17Xml {  //json字符串  static String JsonStr = "{object:{persons:" +      "[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," +      "{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," +      "{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}";  public static void main(String []args) throws JSONException{    List<Person> list=jsonStrToList(JsonStr);    System.out.println(list.size());  }  /**   *   *   *   */  public static List<Person> jsonStrToList(String jsonStr) throws JSONException{    List<Person> list=new ArrayList<Person>();    //通过字符串，获得最外部的json对象    JSONObject jsonObj=new JSONObject(jsonStr);    //通过属性名，获得内部的对象    JSONObject jsonPersons=jsonObj.getJSONObject("object");    //获得json对象组    JSONArray arr=jsonPersons.getJSONArray("persons");    for(int i=0;i<arr.length();i++){      //循环对象，并通过getString("属性名");来获得值      JSONObject tempJson=arr.getJSONObject(i);      Person person=new Person();      person.setName(tempJson.getString("name"));      person.setImage(tempJson.getString("image"));      list.add(person);    }    return list;  }}