1
}
else
{
2
$query = "SELECT main.
id
AS aid,main.*,main.description AS description1,
type
.*
3
FROM $maintable main
4
LEFT JOIN sqarctype
type
ON
type
.
id
= main.typeid
5
LEFT JOIN $addontable addon ON addon.aid = main.
id
6
$where $orderby";
7
}
新闻热点
疑难解答