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ASP.NET技巧:请求网址并解析返回的html

2024-07-10 12:40:46
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  目的,把远程服务器传回的Html,解析到类里面,为GridView等提供数据源

  1 、向远程服务器Post数据

public int PostData(string url, string data, out string info)
        {
            info = "";
            CookieContainer cc = new CookieContainer();
            HttpWebRequest request = WebRequest.Create(url) as HttpWebRequest;
            request.CookieContainer = cc;
            request.Method = "POST";
            request.ContentType = "application/x-www-form-urlencoded";
            Stream requestStream = request.GetRequestStream();
            byte[] byteArray = Encoding.UTF8.GetBytes(data);
            requestStream.Write(byteArray, 0, byteArray.Length);
            requestStream.Close();
            HttpWebResponse response = request.GetResponse() as HttpWebResponse;
            Uri responseUri = response.ResponseUri;
            Stream receiveStream = response.GetResponseStream();
            Encoding encode = System.Text.Encoding.GetEncoding("utf-8");
            StreamReader readStream = new StreamReader(receiveStream, encode);
            string result = readStream.ReadToEnd();
            info = result;
            return 0;
        }

  2、解析返回的html,有省略

public ClassInfo[] GetClass(string html)
        {
            ArrayList ar = new ArrayList();
            ArrayList arr = new ArrayList();
            string table = "";
            Regex regtable = new Regex(@"(?<=<table.*>).*?(?=</table>)", RegexOptions.Singleline);
            Match ma = regtable.Match(html);

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