如何输出第二列相同的行

10999201508261233197418182901054|63a96a66ba024913aa1c0d377cf95fb4||20150826|aa10999201508261233197418182901054|63a96a66ba024913aa1c0d377cf95fb3||20150826|bb

#!/bin/bashi=0a[0]=""while read linedo   newline=`echo $line |cut -d"|" -f2`   for(( j=0;j<=$i;j++ ))   do      if [ "${a[$j]}" = "$newline" ];then          echo $line      fi   done   if [ $[$i+1] -eq $j ];then      i=$[$i+1]      a[$i]=$newline   fidone < 1.txt