jQuery+php简单实现全选删除的方法

<input type="checkbox" id="ckb_selectAll" onclick="selectAll()"  if ($('#ckb_selectAll').is(':checked')) {    $(".ckb").attr("checked", true); //全部选中  } else {    $(".ckb").attr("checked", false);//全部取消  }}

function del_() {  var ids = '';  $(".ckb").each(function() {    if ($(this).is(':checked')) {      ids += ',' + $(this).val(); //逐个获取id    }  });  ids = ids.substring(1); // 对id进行处理，去除第一个逗号  if (ids.length == 0) {    alert('请选择要删除的选项');  } else {    if (confirm("确定删除？删除后将无法恢复。")) {      url = "action=del_call_record&ids=" + ids;      $.ajax({        type: "post",        url: "send.php",        data: url,        success: function(json) {          if (parseInt(json.counts) > 0) {            alert(json.des);            location.reload();          } else {            alert(json.des);          }        },        error: function(XMLHttpRequest, textStatus) {          alert("页面请求错误，请检查重试或联系管理员！/n" + textStatus);        }      });    }  }}

$ids = trim($_REQUEST['ids']);$del_sql = "DELETE FROM vicidial_call_record WHERE id IN(".$ids.")";//print_r($del_sql);exit;if (mysqli_query($db_conn, $del_sql)) {  $counts = "1";  $des = "成功";} else {  $counts = "0";  $des = "失败";}$json_data = "{";$json_data. = "/"counts/":".json_encode($counts).",";$json_data. = "/"des/":".json_encode($des)."";$json_data. = "}";echo $json_data;break;