PHP实现模仿socket请求返回页面的方法

<?php
 $url = "www.XXXX.com";　　//自己做替换
 $parse = parse_url($url);　　//对URL进行解析，返回起组成部分。
 $host = $parse['host'];
 $path = $parse['path'];
 $port = 80;
 $timeout = 80;
 $fp = @fsockopen($host, $port, $errno, $errstr, $timeout);　　//打开socket链接
 if (!$fp){
     echo $errno."--".$errstr;　　//如果错误，则返回错误代码和错误信息
 } else {
     $out = "POST $path HTTP/1.1/r/n";　　//以下是HTTP请求头信息
     $out .= "Host: ".$host."/r/n";
     $out .= "Accept: */*/r/n"; 
     $out .= "Connection: Close/r/n";
     $out .= "Cookie: $cookie/r/n/r/n";
    
     @fwrite($fp, $out);　　//把请求信息写到链接中
     $status = stream_get_meta_data($fp); 
     if(!$status['timed_out']) {     
                 while (!feof($fp)) {  
                     if(($header = @fgets($fp)) && ($header == "/r/n" ||  $header == "/n")) {     
                         break;     
                     }     
                 }     
         
                 $stop = false;     
                 while(!feof($fp) && !$stop) {     
                     $data = fread($fp,8192);      //8192为可返回字节数
                     $return .= $data;         
                 }     
             }     
     fclose($fp);
     print_r($return);
 }