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getJSON跨域SyntaxError问题分析

2024-05-04 23:24:45
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这篇文章主要介绍了getJSON跨域SyntaxError问题分析,需要的朋友可以参考下
 
 

昨天写一个功能:点击手机验证的同时获取json端的数据。

javascript代码如下:

$(".check_mobile").click(function(){var mobile = $('.mobile').val();$.getJSON("http://www.huudi.com/user.php?mobile="+mobile+"&format=json&jsoncallback=?", function(data){if (data.succ == 1) {var html = "<input type='hidden' name='cityid' value='"+data.data.cityid+"'><input type='hidden' name='communityid' value='"+data.data.communityid+"'>";$(".r_m").append(html);}});});

user.php代码如下:

<?phpif($_GET){$mobile = $_GET['mobile'];if ($mobile == 'XXXX') {$user = array('city' =>'石家庄','cityid' =>'1','community' =>'紫晶悦城','communityid'=>'1');$sucess = 1;$return = array('succ' =>$sucess,'data' => $user);}else {$sucess = 2;$return = array('succ' =>$sucess);}echo json_encode($return);}?>

相应如下:

问题出来了:

在火狐浏览器中: SyntaxError: missing ; before statement

解决方法如下:

header("Access-Control-Allow-Origin:http:www.test.com");$b = json_encode($return);echo "{$_GET['jsoncallback']}({$b})";exit;

最后完整代码:

<?phpheader("Access-Control-Allow-Origin:http:www.test.com");if($_GET){$mobile = $_GET['mobile'];if ($mobile == '18831167979') {$user = array('city' =>'石家庄','cityid' =>'1','community' =>'紫晶悦城','communityid'=>'1');$sucess = 1;$return = array('succ' =>$sucess,'data' => $user);}else {$sucess = 2;$return = array('succ' =>$sucess);}$b = json_encode($return);echo "{$_GET['jsoncallback']}({$b})";exit;}?>

如果在 PHP 中少了 header("Access-Control-Allow-Origin:http:www.test.com"); 代码,则会出现

XMLHttpRequest cannot load ''. No 'Access-Control-Allow-Origin' header is present on the requested resource. Origin ' ' is therefore not allowed access.
如果少了 echo "{$_GET['jsoncallback']}({$b})"; 代码

在谷歌浏览器中:Uncaught SyntaxError: Unexpected token :
在火狐浏览器中:SyntaxError: missing ; before statement


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