PHP登录（ajax提交数据和后台校验）实例分享

1.前台ajax数据提交

<form id="login_form" action="" method="POST">  <div class="login_frame" style="position:relative";>    <div class="login_gl" style="margin-top:35px;">      <span class="login_wz" >后台管理系统</span>    </div>    <div class="login_user">      <input id="username" name="username" type="text" placeholder="请输入您的用户名" value="" style="width:100%;height:32px;border-style:none;font-size:16px;color:#959595;"/>    </div>    <div class="login_user">      <input id="password" name="password" type="password" placeholder="请输入您的密码" value="" style="width:100%;height:32px;border-style:none;font-size:16px;color:#959595;"/>    </div>    <div id="login_btn" class="login_log">      <span style="font-size:16px;">登录</span>    </div>  </div>  </form></div><script type="text/javascript">  $("#login_btn").click(function(){    var username = $.trim($("#username").val());    var password = $.trim($("#password").val());    if(username == ""){      alert("请输入用户名");      return false;    }else if(password == ""){      alert("请输入密码");      return false;    }    //ajax去服务器端校验    var data= {username:username,password:password};    $.ajax({      type:"POST",      url:"__CONTROLLER__/check_login",      data:data,      dataType:'json',      success:function(msg){        //alert(msg);        if(msg==1){           window.location.href = "{:U('Index/personal')}";          }else{          alert("登录失败，请重试!");        }      }    });});  </script>

2.后台校验：

* */  public function check_login(){    $password=I('param.password');    $username=I('param.username');    $data["name"]=$username;    $user=M('systemuser');    $list=$user->where($data)->find();    $return=0;    if($list!=""){      if($list['password']==md5($password) && $list['status'] == 1){        //登录时间和登录IP        $public = new PublicController();        $lastlogonip=$public->ip_address();                      $time=$time=date("Y-m-d H:i:s", time());        $where=array('id'=>$list['id']);                $user->where($where)->save(array('lastlogonip'=>$lastlogonip,'lastlogontime'=>$time));        $this->login($list);        $return=1;//登录成功      }    }else{      $return=2;//登录失败    }    $this->ajaxReturn($return);  }

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