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PHP直接修改表内容DataGrid功能实现代码

2024-05-04 22:34:59
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由于需要连接Oracle所以从二次开发和页面样式来说个人觉得phpMyDataGrid还是比较好上手。
1. 创建测试数据库和表

create database `guru`;  USE `guru`;  CREATE TABLE `employees` (    `id` int(6) NOT NULL auto_increment,    `name` char(20) default NULL,    `lastname` char(20) default NULL,    `salary` float default NULL,    `age` int(2) default NULL,    `afiliation` date default NULL,    `status` int(1) default NULL,    `active` tinyint(1) default NULL,    `workeddays` int(2) default NULL,    `photo` char(30) default NULL,    PRIMARY KEY (`id`) )  insert into `employees`   (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)    values (1, 'Ana', 'Trujillo',2000,45, '2005-05-13',1,1,10, '1.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (2, 'Jennifer', 'Aniston',3500,23, '2004-10-22',1,0,0, '2.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (3, 'Michael', 'Norman',1200,19, '2007-01-10',1,1,5, '3.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (4, 'Vanessa', 'Black',6500,31, '2000-11-05',1,1,30, '4.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (5, 'Michael', 'Strauss',3200,45, '2006-10-21',2,0,22, '5.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (6, 'William', 'Brown',2300,21, '2001-03-10',3,1,10, '6.jpg'); insert into `employees`    (`id`,`name`,`lastname`,`salary`,`age`,`afiliation`,`status`,`active`,`workeddays`,`photo`)   values (7, 'Lucca', 'Normany',2800,36, '2006-10-02',3,1,20, '7.jpg'); 

2. PHP程序介绍

phpMyDataGrid主要是通过phpmydatagrid.class.php,dgscripts.js来实现的,总共加起来不到100kB,又是一个小巧的软件。对于这两个文件就不多讲了,感兴趣的同学可以“打包带走”回去慢慢品。主要介绍该软件的使用方法,即实例 datagrid_for_mysql.php。先看一下页面示意图:

程序讲解:

<?php  include ("phpmydatagrid.class.php"); $objGrid = new datagrid; $objGrid->closeTags(true);  $objGrid->friendlyHTML();  $objGrid->methodForm("get");  //连接数据库 $objGrid->conectadb("127.0.0.1", "root", "root", "guru");//加密字符串 $objGrid->salt("Myc0defor5tr0ng3r-Pro3EctiOn"); $objGrid->language("en"); //最后一列显示的功能键,从左向右功能为“新增键”、“编辑键”、“删除键”、“浏览键”。 $objGrid->buttons(true,true,true,true); //修改数值时产生的Form名称 $objGrid->form('employee', true); //可检索列名 $objGrid->searchby("name,lastname"); //需要读取的表 $objGrid->tabla("employees"); //索引值用于修改数据 $objGrid->keyfield("id"); //分页显示行数 $objGrid->datarows(20); //默认排序方式 $objGrid->orderby("name", "ASC"); //显示列设置,相关设置可参考phpmydatagrid.class.php $objGrid->FormatColumn("id", "ID Employee", 5, 5, 1, "50", "center", "integer"); $objGrid->FormatColumn("name", "Name", 30, 30, 0, "150", "left"); $objGrid->FormatColumn("lastname", "Last name", 30, 30, 0, "150", "left"); $objGrid->FormatColumn("age", "Age", 5, 5, 0, "50", "right");//自定义日期格式 $objGrid->FormatColumn("afiliation", "Afiliation Date", 10, 10, 0, "100", "center", "date:dmy:/");//编辑时可以自定义为<Select>模式 $objGrid->FormatColumn("status", "Status", 5, 5, 0, "60", "left", "select:1_Single:2_Married:3_Divorced"); //编辑时可以自定义为<CheckBox>模式 $objGrid->FormatColumn("active", "Active", 2, 2, 0,"50", "center", "check:No:Yes");//自定义货币显示形式 $objGrid->FormatColumn("salary", "Salary", 10, 10, 0, "90", "right", "money:€");//将数据以柱状图显示 $objGrid->FormatColumn("workeddays", "Work days", 5, 2, 0, "50", "right", "chart:percent:val:31"); $objGrid->checkable(); $objGrid->setHeader(); $objGrid->ajax('silent'); echo '<html>    <head><title>PHPDataGrid</title></head>    <body><div align="center"><br />'; //生成DataGrid $objGrid->grid(); echo '</div></body></html>';//关闭数据库连接 $objGrid->desconectar(); ?>             
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