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PHP实现上传文件并存进数据库的方法

2024-04-25 20:39:15
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本文实例讲述了PHP实现上传文件并存进数据库的方法。分享给大家供大家参考。具体如下:

show_add.php文件如下:

<?php

if(!isset($_REQUEST['id']) or $_REQUEST['id']=="") die("error: id none");

$id = $_REQUEST['id'];

//定位记录,读出

$conn=mysql_connect("localhost","root","admin");

if(!$conn) die("error: mysql connect failed");

mysql_select_db("nokiapaymentplat",$conn);

$sql = "select * from receive where id=$id";

$result = mysql_query($sql,$conn);

if(!$result) die("error: mysql query");

$num=mysql_num_rows($result);

if($num<1) die("error: no this recorder");

$data = mysql_result($result,0,"file_data");

$type = mysql_result($result,0,"file_type");

$name = mysql_result($result,0,"file_name");

mysql_close($conn);

//先输出相应的文件头,并且恢复原来的文件名

header("Content-type:$type");

header("Content-Disposition: attachment; filename=$name");

echo $data;

?>

show_info.php文件如下:

<?php

if(!isset($_REQUEST['id']) or $_REQUEST['id']=="") die("error: id none");

$id = $_REQUEST['id'];

//定位记录,读出

$conn=mysql_connect("localhost","root","admin");

if(!$conn) die("error: mysql connect failed");

mysql_select_db("nokiapaymentplat",$conn);

$sql = "select file_name ,file_size from receive where id=$id";

$result = mysql_query($sql,$conn);

if(!$result) die(" error: mysql query");

//如果没有指定的记录,则报错

$num=mysql_num_rows($result);

if($num<1) die("error: no this recorder");

//下面两句程序也可以这么写

//$row=mysql_fetch_object($result);

//$name=$row->name;

//$size=$row->size;

$name = mysql_result($result,0,"file_name");

$size = mysql_result($result,0,"file_size");

mysql_close($conn);

echo "<hr>上传的文件的信息:";

echo "<br>The file's name - $name";

echo "<br>The file's size - $size";

echo "<br><a href=show_add.php?id=$id>附件</a>";

?>

submit.php文件如下:

<?php

if(is_uploaded_file($_FILES['myfile']['tmp_name'])) {

//有了上传文件了

$myfile=$_FILES["myfile"];

//设置超时限制时间,缺省时间为 30秒,设置为0时为不限时

$time_limit=60;

set_time_limit($time_limit); //

//把文件内容读到字符串中

$fp=fopen($myfile['tmp_name'], "rb");

if(!$fp) die("file open error");

$file_data = addslashes(fread($fp, filesize($myfile['tmp_name'])));

fclose($fp);

unlink($myfile['tmp_name']);

//文件格式,名字,大小

$file_type=$myfile["type"];

$file_name=$myfile["name"];

$file_size=$myfile["size"];

die($file_type);

//连接数据库,把文件存到数据库中

$conn=mysql_connect("localhost","root","admin");

if(!$conn) die("error : mysql connect failed");

mysql_select_db("nokiapaymentplat",$conn);

$sql="insert into receive

(file_data,file_type,file_name,file_size)

values ('$file_data','$file_type','$file_name',$file_size)";

$result=mysql_query($sql,$conn);

//下面这句取出了刚才的insert语句的id

$id=mysql_insert_id();

mysql_close($conn);

set_time_limit(30); //恢复缺省超时设置

echo "上传成功--- ";

echo "<a href='show_info.php?id=$id'>显示上传文件信息</a>";

}

else {

echo "你没有上传任何文件";

}

?>

upload.php文件如下:

<head>

<title>文件上传表单</title>

</head>

<body>

<table>

<form enctype='multipart/form-data' name='myform' action='submit.php'

method='post'>

<INPUT TYPE = "hidden" NAME = "MAX_FILE_SIZE" VALUE ="1000000">

<tr><td>选择上传文件</td><td>

<input name='myfile' type='file'></td></tr>

<tr><td colspan='2'><input name='submit' value='上传' type='submit'></td></tr>

</table>

</body>

</html>

希望本文所述对大家的PHP程序设计有所帮助。

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