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浅析Linux下一个简单的多线程互斥锁的例子

2020-10-28 18:49:43
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复制代码 代码如下:

#include <stdio.h>
#include <pthread.h>
pthread_mutex_t Device_mutex ;
int count=0;
void thread_func1()
{
   while(1)
   {
       pthread_mutex_lock(&Device_mutex);
       printf("thread1: %d/n",count);
       pthread_mutex_unlock(&Device_mutex);
       count++;
       sleep(1);
   }
}
void thread_func2()
{
   while(1)
   {
       pthread_mutex_lock(&Device_mutex);
       printf("thread2: %d/n",count);
       pthread_mutex_unlock(&Device_mutex);
       count++;
       sleep(1);
   }
}
int main()
{
   pthread_t thread1, thread2;
   pthread_mutex_init(&Device_mutex,NULL);
   if(pthread_create(&thread1,NULL,(void*)thread_func1,NULL) == -1)
 {
  printf("create IP81 Thread error !/n");
  exit(1);
 }
 sleep(1);
 if(pthread_create(&thread2,NULL,(void *)thread_func2,NULL) == -1)
 {
  printf("create IP81_2 Thread error!/n");
  exit(1);
 }
 sleep(1);
 pthread_join(thread1,NULL);
 pthread_join(thread2,NULL);
 pthread_mutex_destroy(&Device_mutex);
 return 0;
}
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