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linux shell实现求一个多维数组中的最大和最小值

2020-07-27 19:01:24
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同事发了一道shell题,是求一个多维数组中的最大和最小值
如文件 99file:
 
33      55      23      56      99
234     234     545     6546    34
11      43      534     33      75
43      34      76      756     33
343     890     77      667     55

我的实现之一:

#! /bin/bashecho "the file is :"cat 99shumax=0min=999999line=1dnum=$(cat 99shu| wc -l)while (($line<=$dnum))dofor i in $(cat 99shu|head -"$line")    do  ((max<$i))&&max=$i    ((min>$i))&&min=$i    donelet ++linedone echo "the max number is: $max"echo "the min number is : $min"

结果:

the max number is: 6546
the min number is : 11

实现之二:

#! /bin/bash# echo the MAX and the MINecho "the numbers is:"cat 99shumnum=0min=99999while  read line dodeclare -a arr=($line)lnum=$(echo $line | wc -w)i=0while (( $i<$lnum ))do(($mnum<${arr[i]})) && mnum=${arr[i]}(($min>${arr[i]})) && min=${arr[i]}let ++idonedone < 99shuecho "the max number is $mnum"echo "the min number is $min"

实现3,强大的awk

#! /bin/bashecho "the MAX number is: $( cat 99shu | awk '{for(i=1;i<=NF;i++)if(max<$i) max=$i;print max}'|tail -1)"echo "eht MIN number is: $( cat 99shu | awk '{min=999999;for(i=1;i<=NF;i++)if(min>$i)min=$i;print min}'|sort|head -1 )"

实现4:

#!/bin/bashmin=$(cat  99shu | tr "/t" "/n"|tr " " "/n"|sort -n|uniq|grep -v "^$"|head -1)max=$(cat  99shu | tr "/t" "/n"|tr " " "/n"|sort -n|uniq|grep -v "^$"|tail -1)echo "The MAX number is $max"echo "The MIN number is $min"

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