核心代码
当你遇到一个date命令不给力的系统时,可以试试这几个小函数。#日期转天数function date2days { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}date2days `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#天数转日期function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d-%02d-%02d/n",yy,mm,dd) }'}days2date 14839#日期转分钟function date2minutes { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*1440+$4*60+$5 print j }'}date2minutes `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#分钟转日期function minutes2date { echo "$1" | awk '{ i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24); a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d-%02d-%02d %02d:%02d/n",yy,mm,dd,hh,nn) }'}minutes2date 21369299#日期转秒数function date2seconds { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*86400+$4*3600+$5*60+$6 print j }'}date2seconds `echo "2010-08-18 18:59:19" | sed 's/-/ /g;s/:/ /g'`#秒数转日期function seconds2date { echo "$1" | awk '{ i=$1; ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24); a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d-%02d-%02d %02d:%02d:%02d/n",yy,mm,dd,hh,nn,ss) }'}seconds2date 1282157959#日期转毫秒function date2milliseconds { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*86400+$4*3600+$5*60+$6 printf ("%d%s/n",j,$7) }'}date2milliseconds `echo "2010-08-18 18:59:19.073" | sed 's/-/ /g;s/:/ /g;s//./ /g'`#毫秒转日期function milliseconds2date { echo "$1" | awk '{ i=$1; ms=i%1000; i=int(i/1000); ss=i%60; i=int(i/60); nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24); a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d-%02d-%02d %02d:%02d:%02d.%03d/n",yy,mm,dd,hh,nn,ss,ms) }'}milliseconds2date 1282157959073
应用实例:
计算今天的N天之后的日期
#!/bin/bashfunction date2days { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d%02d%02d/n",yy,mm,dd) }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`N=5let days-=$Ndays2date $days
计算某天的N天之后的日期
#!/bin/bashfunction date2days { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d%02d%02d/n",yy,mm,dd) }'}year=2010; month=01; day=20days=`date2days $year $month $day`let days+=5days2date $days
计算上一个星期的全部日期
#!/bin/bashfunction date2days { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d%02d%02d/n",yy,mm,dd) }'}function date2week { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7; print dow }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`week=`date2week $year $month $day`let dateEnd=$days-$week-1let dateBegin=$dateEnd-6for ((i=$dateBegin;i<=$dateEnd;i++)); do days2date $idone
日期时间转换成毫秒
function date2milliseconds { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*86400+$4*3600+$5*60+$6 print j$7 }'}date2milliseconds `echo "2010-08-18 18:59:19.073" | /usr/xpg4/bin/awk -F'[:.-]+' '$1=$1'`
日期时间转换成秒
function date2seconds { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*86400+$4*3600+$5*60+$6 print j }'}date2seconds `echo "2010-07-21 00:00:00" | sed 's/-/ /g;s/:/ /g'`
判断一个数字是否为合法日期
function date2days { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d%02d%02d/n",yy,mm,dd) }'}num1=20105050num2=20101001arg1=`echo "$num1" | sed -r 's/(....)(..)(..)//1 /2 /3/g'`arg2=`echo "$num2" | sed -r 's/(....)(..)(..)//1 /2 /3/g'`days1=`date2days $arg1`date1=`days2date $days1`days2=`date2days $arg2`date2=`days2date $days2`[ "$num1" -eq "$date1" ] && echo "$num1 is valid date" || echo "$num1 is invalid date"[ "$num2" -eq "$date2" ] && echo "$num2 is valid date" || echo "$num2 is invalid date"
计算10分钟之前的时间
function date2minutes { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; j=j*1440+$4*60+$5 print j }'}function minutes2date { echo "$1" | awk '{ i=$1; nn=i%60; i=int(i/60); hh=i%24; dd=int(i/24); i=int(i/24); a=i+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d-%02d-%02d %02d:%02d/n",yy,mm,dd,hh,nn) }'}now=`date "+%Y-%m-%d %H:%M" | sed 's/-/ /g;s/:/ /g'`minutes=`date2minutes $now`let minutes-=10minutes2date $minutes
计算指定日期和当前系统日期之家相差多少天
#!/bin/bashfunction date2days { echo "$*" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}echo "Enter your date:"read inputInpuDays=$(date2days ${input:0:4} ${input:4:2} ${input:6:2})SysDays=$(date2days `date +"%Y %m %d"`)let result=$InpuDays-$SysDaysecho $result
#./test.shEnter your date:2011060525
上个星期周一的日期
#!/bin/bashfunction date2days { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; j=int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472633; print j }'}function days2date { echo "$1" | awk '{ a=$1+2472632; b=int((4*a+3)/146097); c=int((-b*146097)/4)+a; d=int((4*c+3)/1461); e=int((-1461*d)/4)+c; m=int((5*e+2)/153); dd=-int((153*m+2)/5)+e+1; mm=int(-m/10)*12+m+3; yy=b*100+d-4800+int(m/10); printf ("%4d%02d%02d/n",yy,mm,dd) }'}function date2week { echo "$1 $2 $3" | awk '{ z=int((14-$2)/12); y=$1+4800-z; m=$2+12*z-3; dow=(int((153*m+2)/5)+$3+y*365+int(y/4)-int(y/100)+int(y/400)-2472629)%7; print dow }'}year=`date +%Y`; month=`date +%m`; day=`date +%d`days=`date2days $year $month $day`week=`date2week $year $month $day`let date=$days-$week-7days2date $date
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