Dos下获取系统时间的代码

2020-07-26 20:17:34

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复制代码代码如下:

  
rem DOS get current time  
rem =======================  
rem get yyyy/mm/dd  
set mydate=%DATE:~0,10%  
echo %mydate%  
rem =======================  
rem get yyyy  
set yyyy=%DATE:~0,4%  
echo %yyyy%  
rem =======================  
rem get mm  
set mm=%DATE:~5,2%  
echo %mm%  
rem =======================  
rem get dd  
set dd=%DATE:~8,2%  
echo %dd%  
rem =======================  
rem get yyyy-mm-dd  
set curdate=%yyyy%-%mm%-%dd%  
echo %curdate% 

其实bat中获取时间就是利用截取日期字符串的方法

DOS下有字符处理的方法的，总结如下：

在这个日期格式下：”2013-07-22 星期一”，这个%DATE:~0,10%得到的是2013-07-22
说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。

输出：

C:/Documents and Settings/Administrator>rem DOS get current time
C:/Documents and Settings/Administrator>rem =======================
C:/Documents and Settings/Administrator>rem get yyyy/mm/dd
C:/Documents and Settings/Administrator>set mydate=2013-07-22
C:/Documents and Settings/Administrator>echo 2013-07-22
2013-07-22
C:/Documents and Settings/Administrator>rem =======================
C:/Documents and Settings/Administrator>rem get yyyy
C:/Documents and Settings/Administrator>set yyyy=2013
C:/Documents and Settings/Administrator>echo 2013
2013
C:/Documents and Settings/Administrator>rem =======================
C:/Documents and Settings/Administrator>rem get mm
C:/Documents and Settings/Administrator>set mm=07
C:/Documents and Settings/Administrator>echo 07
07
C:/Documents and Settings/Administrator>rem =======================
C:/Documents and Settings/Administrator>rem get dd
C:/Documents and Settings/Administrator>set dd=22
C:/Documents and Settings/Administrator>echo 22
22
C:/Documents and Settings/Administrator>rem =======================
C:/Documents and Settings/Administrator>rem get yyyy-mm-dd
C:/Documents and Settings/Administrator>set curdate=2013 -07 -22
C:/Documents and Settings/Administrator>echo 2013 -07 -22
2013 -07 -22
C:/Documents and Settings/Administrator>

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