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iOS禁止所有输入法表情的方法

2020-07-26 02:23:16
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本文实例为大家分享了iOS禁止所有输入法表情的具体代码,供大家参考,具体内容如下

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {  //禁止所有输入法的表情  if ([self isContainsTwoEmoji:text]) {    return NO;  }  return YES;}

//判断是否是表情字符

- (BOOL)isContainsTwoEmoji:(NSString *)string {  __block BOOL isEomji = NO;  [string enumerateSubstringsInRange:NSMakeRange(0, [string length]) options:NSStringEnumerationByComposedCharacterSequences usingBlock:   ^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop) {     const unichar hs = [substring characterAtIndex:0];     //     NSLog(@"hs++++++++%04x",hs);     if (0xd800 <= hs && hs <= 0xdbff) {       if (substring.length > 1) {         const unichar ls = [substring characterAtIndex:1];         const int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;         if (0x1d000 <= uc && uc <= 0x1f77f)         {           isEomji = YES;         }         //         NSLog(@"uc++++++++%04x",uc);       }     } else if (substring.length > 1) {       const unichar ls = [substring characterAtIndex:1];       if (ls == 0x20e3|| ls ==0xfe0f) {         isEomji = YES;       }       //       NSLog(@"ls++++++++%04x",ls);     } else {       if (0x2100 <= hs && hs <= 0x27ff && hs != 0x263b) {         isEomji = YES;       } else if (0x2B05 <= hs && hs <= 0x2b07) {         isEomji = YES;       } else if (0x2934 <= hs && hs <= 0x2935) {         isEomji = YES;       } else if (0x3297 <= hs && hs <= 0x3299) {         isEomji = YES;       } else if (hs == 0xa9 || hs == 0xae || hs == 0x303d || hs == 0x3030 || hs == 0x2b55 || hs == 0x2b1c || hs == 0x2b1b || hs == 0x2b50|| hs == 0x231a ) {         isEomji = YES;       }     }   }];  return isEomji;}

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