SQL根据指定分隔符分解字符串实现步骤

2020-07-25 13:12:23

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如果有一个字符串 eg: "sun,star,moon,clouds",想要在MS SQL中根据给定的分隔符','把这个字符串分解成各个元素[sun] [star] [moon] [clouds]，如何实现呢？为此，创建一个Function,代码如下:

复制代码代码如下:

 
CREATE FUNCTION [dbo].[Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) 
RETURNS @temptable TABLE (items VARCHAR(8000)) 
AS 
BEGIN 
DECLARE @idx INT 
DECLARE @slice VARCHAR(8000) 
SELECT @idx = 1 
IF len(@String)<1 OR @String IS NULL RETURN 
while @idx!= 0 
BEGIN 
SET @idx = charindex(@Delimiter,@String) 
IF @idx!=0 
SET @slice = LEFT(@String,@idx - 1) 
ELSE 
SET @slice = @String 
IF(len(@slice)>0) 
INSERT INTO @temptable(Items) VALUES(@slice) 
SET @String = RIGHT(@String,len(@String) - @idx) 
IF len(@String) = 0 break 
END 
RETURN 
END 

示例：如果输入
SELECT * FROM dbo.Split_StrByDelimiter('sun,star,moon,clouds',',')
结果返回
sun
star
moon
clouds
在上面的代码做变形，返回有多少个元素

复制代码代码如下:

 
CREATE FUNCTION [dbo].[GetCount_Split_StrByDelimiter](@String VARCHAR(8000), @Delimiter CHAR(1)) 
RETURNS INT 
AS 
BEGIN 
DECLARE @temptable TABLE (items VARCHAR(8000)) 
DECLARE @SplitCount INT 
DECLARE @idx INT 
DECLARE @slice VARCHAR(8000) 
SELECT @idx = 1 
IF len(@String)<1 OR @String IS NULL RETURN 0 
while @idx!= 0 
BEGIN 
SET @idx = charindex(@Delimiter,@String) 
IF @idx!=0 
SET @slice = LEFT(@String,@idx - 1) 
ELSE 
SET @slice = @String 
IF(len(@slice)>0) 
INSERT INTO @temptable(Items) VALUES(@slice) 
SET @String = RIGHT(@String,len(@String) - @idx) 
IF len(@String) = 0 break 
END 
SET @SplitCount=(SELECT COUNT(*) FROM @temptable) 
RETURN @SplitCount 
END 