把字符串 “c:/test/1” 中的 “/” 全部替换成 “//” 的原理:
(假设 "C:/TEST/1” 字符串已存在 VAR 变量中:)
C:/WINDOWS>set "var=C:/TEST/1"
(将 var 变量中的字符串里 "/" 字符全部替换成 "//")
C:/WINDOWS>set "var=%var:/=//%"
(显示 var 变量中的内容)
C:/WINDOWS>echo %var%
C://TEST//1
结果为:C://TEST//1 ,已全部替换完成。
下面给几个其他网友给的例子
文件字符串替换
@echo offecho ***** Replace "abcd" as "ABCD" *****set strFilePath=C:/Users/Leez/Desktop/TestBat/TestSource.txtset strOld=abcdset strNew=ABCDsetlocal enabledelayedexpansionfor /f "tokens=*" %%i in (%strFilePath%) do ( set "var=%%i" if not !var!.==. ( set "var=!var:%strOld%=%strNew%!" echo !var!!>>%strFilePath%.bk ))move /y %strFilePath%.bk %strFilePath%pause |
例子二:
@echo off setlocal enabledelayedexpansion set file= set /p file= 请输入要操作的文件名称(包括扩展名): set "file=%file:"=%" for %%i in ("%file%") do set file=%%~fi echo. set replaced= set /p replaced= 请输入即将被替换的内容: echo. set all= set /p all= 请输入替换字符串: for /f "delims=" %%i in ('type "%file%"') do ( set str=%%i set "str=!str:%replaced%=%all%!" echo !str!>>"%file%"_tmp.txt ) copy "%file%" "%file%"_bak.txt >nul 2>nul move "%file%"_tmp.txt "%file%" start "" "%file%" |
笔者将它更改一下
把16改为17
@echo off setlocal enabledelayedexpansion set file=c:/Program Files/hndsclient/ds/GetFile.iniset "file=%file:"=%" for %%i in ("%file%") do set file=%%~fi echo. set replaced=16 echo. set all=17for /f "delims=" %%i in ('type "%file%"') do ( set str=%%i set "str=!str:%replaced%=%all%!" echo !str!>>"%file%"_tmp.txt ) copy "%file%" "%file%"_bak.txt >nul 2>nul move "%file%"_tmp.txt "%file%" start "" "%file%" |
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