C++实现十六进制字符串转换成int整形值的示例

#include <stdio.h>#include <string.h>//字符转换成整形int hex2int(char c){ if ((c >= 'A') && (c <= 'Z')) { return c - 'A' + 10; } else if ((c >= 'a') && (c <= 'z')) { return c - 'a' + 10; } else if ((c >= '0') && (c <= '9')) { return c - '0'; }}int main(){ //十六进制字符串转换成整形 const char* hexStr = "EFA0"; int data[32] = {0}; int count = 0; for (int i=0; i<strlen(hexStr); i+=2) { int high = hex2int(hexStr[i]);  //高四位 int low = hex2int(hexStr[i+1]); //低四位 data[count++] = (high<<4) + low; } //打印输出 for (int i=0; i<strlen(hexStr)/2; i++) { printf("%d ", data[i]); } return 1;}