接触过Android开发的同学们都知道在Android中访问程序资源基本都是通过资源ID来访问。这样开发起来很简单，并且可以不去考虑各种分辨率，语言等不同资源显式指定。
但是，有时候也会有一些问题，比如我们根据服务器端的值取图片，但是服务器端绝对不会返回给我们的是资源id，最多是一种和文件名相关联的值，操作资源少的时候，可以维护一个容器进行值与资源ID的映射，但是多的话，就需要另想办法了。
Resources res = getResources();
final String packageName = getPackageName();
int imageResId = res.getIdentifier("ic_launcher", "drawable", packageName);
int imageResIdByAnotherForm = res.getIdentifier(packageName + ":drawable/ic_launcher", null, null);
int musicResId = res.getIdentifier("test", "raw", packageName);
int notFoundResId = res.getIdentifier("activity_main", "drawable", packageName);
Log.i(LOGTAG, "testGetResourceIds imageResId = " + imageResId
+ ";imageResIdByAnotherForm = " + imageResIdByAnotherForm
+ ";musicResId=" + musicResId
+ ";notFoundResId =" + notFoundResId);
**
* Return a resource identifier for the given resource name. A fully
* qualified resource name is of the form "package:type/entry". The first
* two components (package and type) are optional if defType and
* defPackage, respectively, are specified here.
*
* <p>Note: use of this function is discouraged. It is much more
* efficient to retrieve resources by identifier than by name.
*
* @param name The name of the desired resource.
* @param defType Optional default resource type to find, if "type/" is
* not included in the name. Can be null to require an
* explicit type.
* @param defPackage Optional default package to find, if "package:" is
* not included in the name. Can be null to require an
* explicit package.
*
* @return int The associated resource identifier. Returns 0 if no such
* resource was found. (0 is not a valid resource ID.)
*/
public int getIdentifier(String name, String defType, String defPackage) {
try {
return Integer.parseInt(name);
} catch (Exception e) {
// Ignore
}
return mAssets.getResourceIdentifier(name, defType, defPackage);
}
