在Android开发的过程中,必须暴露于数据交互,由于您暴露于数据交互,所以很自然地使用通信之间的协议来请求,本文是武林技术频道小编给大家介绍的Android使用httpPost向服务器发送请求的方法,一起来看看吧!
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import java.util.List;import org.apache.http.HttpEntity;import org.apache.http.HttpResponse;import org.apache.http.NameValuePair;import org.apache.http.client.HttpClient;import org.apache.http.client.entity.UrlEncodedFormEntity;import org.apache.http.client.methods.HttpPost;import org.apache.http.conn.ConnectTimeoutException;import org.apache.http.impl.client.DefaultHttpClient;import org.apache.http.params.CoreConnectionPNames;import org.apache.http.protocol.HTTP;import org.apache.http.util.EntityUtils;import android.util.Log;public class RequestByHttpPost { public static String TIME_OUT = "操作超时"; public static String doPost(List<NameValuePair> params,String url) throws Exception{ String result = null; // 新建HttpPost对象 HttpPost httpPost = new HttpPost(url); // 设置字符集 HttpEntity entity = new UrlEncodedFormEntity(params, HTTP.UTF_8); // 设置参数实体 httpPost.setEntity(entity); // 获取HttpClient对象 HttpClient httpClient = new DefaultHttpClient(); //连接超时 httpClient.getParams().setParameter(CoreConnectionPNames.CONNECTION_TIMEOUT, 30000); //请求超时 httpClient.getParams().setParameter(CoreConnectionPNames.SO_TIMEOUT, 30000); try { // 获取HttpResponse实例 HttpResponse httpResp = httpClient.execute(httpPost); // 判断是够请求成功 if (httpResp.getStatusLine().getStatusCode() == 200) { // 获取返回的数据 result = EntityUtils.toString(httpResp.getEntity(), "UTF-8"); Log.i("HttpPost", "HttpPost方式请求成功,返回数据如下:"); Log.i("result", result); } else { Log.i("HttpPost", "HttpPost方式请求失败"); } } catch (ConnectTimeoutException e){ result = TIME_OUT; } return result; }}本文是武林技术频道小编为大家带来的Android使用httpPost向服务器发送请求的方法,大家了解的怎样了呢?武林技术频道小编将竭尽为大家找寻有用的知识。
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