首页 > 编程 > Python > 正文

python抓取文件夹的所有文件

2019-11-25 15:08:27
字体:
来源:转载
供稿:网友

本文实例为大家分享了python抓取文件夹的所有文件的具体代码,供大家参考,具体内容如下

#!/user/bin/python # -*- coding:utf8 -*-  import Basic import os  ##################################################### ########    Input      #### folder = "D://安装包" folder = folder.encode("gbk")  ########    Global      #### fileList = [] allFiles = [] tree = [] level = 0 #####################################################  try:  if folder is None or len(folder) == 0:   folder = os.curdir   if os.path.isdir(folder):   childFile = os.listdir(folder)   fileList = ["%s" % (folder+os.path.sep+f) for f in childFile]    node = {'file':folder, 'level':level}   tree.append(node)    while fileList is not None and len(fileList) > 0:    allFiles.append(""+fileList[0])     if os.path.isdir(fileList[0]):     childFile = os.listdir(fileList[0])      if childFile is not None and len(childFile) > 0:      fileList = fileList + ["%s" % (fileList[0]+os.path.sep+ft) for ft in childFile]     else:      pass    else:     pass     fileList.pop(0)    print "/n".join(["%s" % f for f in allFiles])  else:   print 'not folder, no child'  except Exception,x:  print x 

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持武林网。

发表评论 共有条评论
用户名: 密码:
验证码: 匿名发表